(x^2-1/5x)*(6x/x-1)

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Solution for (x^2-1/5x)*(6x/x-1) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(x^2-((1/5)*x))*((6*x)/x-1) = 0

(x^2+(-1/5)*x)*((6*x)/x-1) = 0

5*(x^2-1/5*x) = 0

x^2-1/5*x = 0

x*(x-1/5) = 0

x-1/5 = 0 // + 1/5

x = 1/5

x*(x-1/5) = 0

5*x*(x-1/5) = 0

( 5 )

5 = 0

x belongs to the empty set

( x-1/5 )

x-1/5 = 0 // + 1/5

x = 1/5

( x )

x = 0

x in { 0} 

x = 1/5

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